
Arturo O. answered 11/04/19
Experienced Physics Teacher for Physics Tutoring
I assume you meant to say that the zero of 1 has multiplicity of 2.
f(x) = ax(x - 1)2
f(2) = 10 ⇒
a(2)(2 - 1)2 = 10
a = 5
f(x) = 5x(x - 1)2
Test the answer.
Stephanie C.
asked 11/03/19Find a polynomial function f(x) of degree 3 with real coefficients that satisfies the following conditions.
Zero of 0 and Zero of 1 have multiplicity 2; f(2)=10
Arturo O. answered 11/04/19
Experienced Physics Teacher for Physics Tutoring
I assume you meant to say that the zero of 1 has multiplicity of 2.
f(x) = ax(x - 1)2
f(2) = 10 ⇒
a(2)(2 - 1)2 = 10
a = 5
f(x) = 5x(x - 1)2
Test the answer.
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