Lynn W. answered 01/23/15
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Cornell Grad For Math & CS Tutoring
Edit: While I was writing this, I saw that you got another answer from someone else. I guess I'll leave my answer here anyway, though, in case it helps haha.
Hi Kelly,
The first thing to do would be to figure out what "point-slope" is asking for. From what I know, it means the (linear) equation uses the slope of the line as well as a point on the line (hence the name).
So, we have to find the slope of the line. We are given two points, so we can use those:
(x1,y1) = (-4,6)
(x2,y2) = (1,2)
m = (y2-y1)/(x2-x1) = (2-6)/(1--4) = (2-6)/(1+4) = -4/5
Also, we know that point-slope is of the form:
(y-y1) = m*(x-x1)
It doesn't matter which point you use, though, you can also use:
(y-y2) = m*(x-x2)
So we can plug the variables into the equation and get:
(y-2) = -4/5*(x-1)
OR
(y-6) = -4/5*(x+4)
Multiplying out the two point-slope forms and simplifying give the same equation in slope-intercept form: y = mx+b.
The first thing to do would be to figure out what "point-slope" is asking for. From what I know, it means the (linear) equation uses the slope of the line as well as a point on the line (hence the name).
So, we have to find the slope of the line. We are given two points, so we can use those:
(x1,y1) = (-4,6)
(x2,y2) = (1,2)
m = (y2-y1)/(x2-x1) = (2-6)/(1--4) = (2-6)/(1+4) = -4/5
Also, we know that point-slope is of the form:
(y-y1) = m*(x-x1)
It doesn't matter which point you use, though, you can also use:
(y-y2) = m*(x-x2)
So we can plug the variables into the equation and get:
(y-2) = -4/5*(x-1)
OR
(y-6) = -4/5*(x+4)
Multiplying out the two point-slope forms and simplifying give the same equation in slope-intercept form: y = mx+b.