Solve the following question.

Question

Find the points on the curve y=x^2+3x-7 at which the slope of the tangent line is equal to 4.

Answer 1

The slope of the tangent line at a point on a curve is equal to the first derivative of the curve's function y(x). Since we have y = x² + 3x - 7, we have y' = 2x + 3. Because you want the slope of the tange line to equal 4, let y' = 4, so 4 = 2x + 3. Now it should be easy to solve.