Irene R. answered 10/20/19
Senior Mechanical Engineer with 13+ years of Teaching Experience
If we let x represent the number of student tickets sold and y be the number of non-students tickets sold, then we can write the following 2 equations to solve the problem:
x + y = 508 (Equation for number of tickets)
3x + 5y = 1814 (equation for cost of tickets)
Then use substitution to solve the two equations with two unknowns= 290
x = 508 -y
Substitute this expression for x in the cost equation:
3(508 - y) + 5y = 1814
Solve for y using the distributive property , combining like terms, and inverse operations:
1524 - 3y + 5y = 1814
1524 +2y = 1814
1524 + 2y -1524 = 1814 -1524
2y = 290
2y/2 = 290/2
y= 145 non-student tickets
x = 508 - y OR
x= 508 - 145
x =363 student tickets
To check:
145 * $5 + 363 * $3 = $1814
$725 + $1089 = $1814