How many gallons each of 25​% alcohol and 5​% alcohol should be mixed to obtain 20 gal of 22​% ​alcohol?

Answer 1

.25x+.05(20-x)= .22(20)

x = gallons of 25%

20-x = gallons of 5%

.2x= .17(20

x= .17(20)/.2= 1.7/,1= 17 gal 25%, 3 gal 5%

25-22 = 3

22-5 = 17

they should be in a 17/3 ratio