Since x Ω y = 2y Ω 3, we have (x - y)2 = (2y - 3)2. But, x = y - 3.
So, (y - 3 - y)2 = (2y - 3)2
9 = 4y2 - 12y + 9
4y2 - 12y = 0
4y(y - 3) = 0
y = 0 or y = 3
ANSWER: C
Justin R.
asked 01/22/15
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