Raymond B. answered 08/04/25
Math, microeconomics or criminal justice
sum of integers formula from 1 to n = n(n+1)/2 = Gauss' formula
basic step in math induction n=1
1 = 1(1+1)/2= 2/2
n=2
1+2 =3, 2(2+1)/2 = 3
n=3
1+2+3= 6 3(3+1)/2 = 6
inductive step
assume it's true for n=k
try to show it works for k+1. add k+1 to both sides, then manipulate the right side
1+2+...+k +k+1 = k(k+1)/2 + k +1
rewrite so right side = (k+1)((k+1)+1)/2 so k+1 replaces k in the original formula
1+...k+1 = (k(k+1) + 2k +2)/2 = (k(k+1)+2(k+1))/2 = (k+1)(k+2)/2 = (k+1)((k+1)+1)/2 TaDa
QED
that's proof by "weak induction"
"strong induction" assumes it's true for all k < n, then proves it's true for k=n
anything provable by strong induction is provable by weak induction