Raymond B. answered 01/13/26
Math, microeconomics or criminal justice
y= 1(x-0)^2 +0
y= 1(x-0)^2 + (-3)
y= 1(x-2)^2 +(-4)
y= 1(x-3)^2 + 3
y= 1(x-2)^2 + 1
y= 1(x+2)^2 + 1
y= -1(x+2)^2 + (-1)
y= -1(x-2)^2 + 1
Johnny L.
asked 10/07/19Convert each of the following quadratic functions into the form y= a(x-p)^2 +q
y= x^2
y= x^2 -3
y= x^2 -4x
y= x^2 -6x +12
y= x^2 -4x +5
y= x^2 +4x +5
y= -x^2 -4x -5
y= -x^2 +4x -5
Raymond B. answered 01/13/26
Math, microeconomics or criminal justice
y= 1(x-0)^2 +0
y= 1(x-0)^2 + (-3)
y= 1(x-2)^2 +(-4)
y= 1(x-3)^2 + 3
y= 1(x-2)^2 + 1
y= 1(x+2)^2 + 1
y= -1(x+2)^2 + (-1)
y= -1(x-2)^2 + 1
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.