Given =g(x) = x^2 - 4x, find the equation of the secant line passing through (−4, g (−4)) and (2, g (2)). Write your answer in the form y = mx + b.

Answer 1

g(x) = x^2 -4x, g(-4) = 16+16 = 32, g(2) = 4-8 =-4

points are (-4,32), (2,-4)

slope = m =(32+4)/(-4-2)= 36/-6 =-6

secant line is y = -6x +b, plug in either point to find b

-4 = -12 +b

b = 12-4 = 8

secant line equation is y =-6x +8