DESCRIBE AND CORRECT THE ERROR.

Question

(3y + 2)^2

= (3y)^2 + (2)^2

=9y^2 + 4

Answer 1

EXPONENT CANNOT BE DISTRIBUTED !!!

EX. (2+1)^2 IS NOT 2^2 + 1^2 = 4 + 1 = 5 because it is not the same as 3^2 = 9

Instead

(3y+2)^2 = (3y + 2)(3y +2) = 9y^2 + 6y + 6y + 4 = 9y^2 + 12y + 4