The sum of 4 consecutive odd integers is 96. What is the least of these 4 integers?

Question

a) 19

b) 21

c) 23

d) 25

e) 27

Answer 1

let x = the least odd integer

x+2 = the 2nd odd integer

x+ 4 = the 3rd odd integer

x+6 = the 4th odd integer

x+x+2+x+4+x+6 = 96

4x+12 = 96

4x = 84

x=21

b)21

Answer 2

The short way:

4n + 12 = 96

4n = 84

n = 21

n + n + 2 + n + 4 + n + 6 = 96