A total of 120 pretzels are divided among three boxed in the ratio of 3 to 4 to 5. How many pretzels are in the box with the fewest pretzels?
The smallest amount would be 1 times the ratio. Thus 3+4+5 or 12 total pretzels. (3x2)+(4x2)+(5x2) is in the same ratio. All are multiplied by 2. In fact there are infinitely many pretzel combinations that it could be but the first one I mentioned would be the smallest.