If we call "level" n, then XP=(n2-n)/2
and the sum of XP=(1/6)(n3-n)
This was derived from the calculus of finite differences.
If you need more education on this topic, try a reference by Jordan, "Calculus of Finite Differences".
Mine Bot B.
asked 09/29/19level = constant * sqrt(XP)
Level | XP | Difference
1 | 0 | -
2 | 100 | 100
3 | 300 | 200
4 | 600 | 300
5 | 1000 | 400
6 | 1500 | 500
7 | 2100 | 600
8 | 2800 | 700
9 | 3600 | 800
10 | 4500 | 900
Looking for an equation to calculate total exp needed for said level
for example, if I were to calculate total exp for level 10, it would be 16500
(0+100+300+600+1000+1500+2100+2800+3600+4500)
If we call "level" n, then XP=(n2-n)/2
and the sum of XP=(1/6)(n3-n)
This was derived from the calculus of finite differences.
If you need more education on this topic, try a reference by Jordan, "Calculus of Finite Differences".
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