How would i find the width and length

Question

A new Youth Activity Center Youth Activity Center is being built in

Junction City Junction City. The perimeter of the rectangular playing field is 232 yards. The length of the field is 44 yards less than

double the width. What are the dimensions of the playing​ field? What is the width and length?

Answer 1

P=232 = 2L +2w

116 = L+2w

L = 2w-44

116 = 2w-44 +w = 3w -44

3w = 116+44 = 160

w = 53 1/3 yards wide

L = 2w-44 = 106 2/3 -44 = 62 2/3 yards Long