Raymond B. answered 08/02/25
Math, microeconomics or criminal justice
P = 228 = 2L +2w
114 = L+w = L+L-46 = 2L -46
2L = 114+46 = 160
L = 160/2 = 80 feet Long
w = 114-80 = 34 feet wide
Jasper L.
asked 09/19/19Write and solve an equation to answer the question
The perimeter of a standard tennis court when used for doubles play is 228 ft. The width is 46ft less than the length. Find the dimensions
Raymond B. answered 08/02/25
Math, microeconomics or criminal justice
P = 228 = 2L +2w
114 = L+w = L+L-46 = 2L -46
2L = 114+46 = 160
L = 160/2 = 80 feet Long
w = 114-80 = 34 feet wide
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