Let x = time driven by the second car needed to catch up to the first car
Distance = (Rate)(Time)
The second car catches up to the first when the distances are equal
So, 50(x + 1) = 65x
50x + 50 = 65x
15x = 50
x = 3 1/3 hr
Sebastian N.
asked 09/16/19A car leaves Beloit, heading east at 50 mph. One hour later, a second car leaves Beloit, heading east at 65 mph. How long will it take for the second car to overtake the first car?
Let x = time driven by the second car needed to catch up to the first car
Distance = (Rate)(Time)
The second car catches up to the first when the distances are equal
So, 50(x + 1) = 65x
50x + 50 = 65x
15x = 50
x = 3 1/3 hr
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