the product of two positive numbers is  22 find the two numbers if one number is  7 more than twice the other

Answer 1

xy=22, x=7+2y

(7+2y)y = 22

2y^2 +7y -22 = 0

factor, set each factor = 0, solve for y

(2y+ 11)(y-2) = 0

y = 2 or -5.5

x = 11 or -4

answer (x,y) = (11, 2) as alternative has negative numbers