Mark M. answered 09/08/19
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Let x = distance of car A from point C at time t
y = distance of car B from point C at time t
z = distance between the cars at time t
Given: dx/dt = -100 and dy/dt = -90
Find: dz/dt when x = 64 and y = 61
x2 + y2 = z2
When x = 64 and y = 61, z = √[642 + 612] = √7817
2x(dx/dt) + 2y(dy/dt) = 2z(dz/dt)
dz/dt = [x(dx/dt) + y(dy/dt)] / z = -11890/√7817 = -134.48
The cars are approaching each other at the rate of 134.48 mph when car A is 64 miles from the intersection and car B is 61 miles from the intersection.