A rectangular room is 2 times as long as it is wide, and its perimeter is 48 meters. Find the dimension of the room.

Answer 1

Let's read the problem carefully:

it says that one side of the rectangular room (let's call it b) is twice as long as the other (let's call it a), which in mathematical terms would be b = 2*a

It also says that the perimeter of the room is 48 meters, which means that (a + b)*2 = 48 => a + 2*a = 48/2 =>

3*a = 24 => a = 8, b = 16

Answer 2

The first step would be to form variables:

Let 'l' represent length, and 'w' represent width.

The room is 2 times as long as it is wide, therefore this can be written as 2w = l

The perimeter of a rectangle is : 2(w+l), which for this question could also be written as 2 (w+ 2w)

Therefore the perimeter = 6w which is equal to 48 m.

6w = 48, therefore w=8

if w=8, and 2w=l, then l=16

Therefore, the dimensions for this rectangle are: width=8 cm, and length= 16 cm.