make x the subject

Question

y=√(3x-2)/(x+1)

make x the subject

Answer 1

y = sqr((3x-2)/(x+1))

square both sides

y^2 = (3x-2)/(x+1)

xy^2 +y^2 = 3x-2

combine like terms of x

3x -xy^2 +y^2+2 = 0

x(3-y^2) = -(y^2 +2)

x = (y^2+2)/(y^2-3)

Unless you really meant y=(sqr(3x-2))/(x+1) then

y^2 = (3x-2)/(x-1)^2 = (3x-2)/(x^2 -2x +1)

x^2y^2 -2y^2x + y^2 use quadratic formula

x = 2y^2/2y^2 +/-(1/2y^2)sqr(4y^4 -4y^4)

x = 1 +/- 1/2y^2

x = 1+1/y^2 or 1-1/y^2

you should check answers to make sure there are no extraneous solutions