Algebra missing words in equation?

Question

Find three consecutive integers such that 105 more than three times the second integer is equal to four times the third integer.

Answer 1

105+3x = 4(x+1) = 4x+4

105-4 = 4x-3x

x = 101

100, 101, & 102 are the 3 consecutive integers

105+3(101) = 4(102)

105 +303 = 408