
Samuel I. answered 08/31/19
Multi-Variable Calculus and Below
Well, this is a bad problem, but let's walk it through. We can use the formula for the area of a trapezoid to solve for what the questions asks.
A = h * (a+b)/2
We are given h and we know A, a, and b are all in terms of one variable, x
Since we have one variable and one equation, we can solve the problem. Let's substitute all our quantities into the area equation like so:
35/x = 10 * (2/x + 8/x + 1)/2
Simplifying the right-hand side a little, we get:
35/x = 5 * (10/x + 1)
And a little more:
35/x = 50/x + 5
Now, If we multiply both sides by x, we get:
35 = 50 + 5x
Finally, if we subtract 50 from both sides and divide by 5, we get:
x = -3
And that's bad because no geometry can have a negative value. I would tell your teacher to revise it so that the area is at least 60/x.
If anyone finds an error in my work, please point it out.