find two consecutive odd integers whose sum is 116?

Answer 1

Let n + 1 and n + 3 be the integers, then:

n + 1 + n + 3 = 116

2n + 4 = 116

2n = 112

n = 56

n + 1 = 57

n + 3 = 59

thus the integers are: 57 and 59