Equation of line: y = mx + b, where m is the slope and (0,b) is the y-intercept.
So, y = -5x + b
Since (3,4) is a point on the line, we have 4 = -5(3) + b. So, b = 19
y = -5x + 19
Sara G.
asked 08/27/19A line passes through the point (3,4) and has a slope of -5. How do I write an equation for this line?
Equation of line: y = mx + b, where m is the slope and (0,b) is the y-intercept.
So, y = -5x + b
Since (3,4) is a point on the line, we have 4 = -5(3) + b. So, b = 19
y = -5x + 19
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