The length of a new rectangular playing field is 6 yards longer than double the width. If the perimeter of the rectangle playing field is 348 yards, what are it’s demensions

Answer 1

P=348, L=6+2w

348 = 2L+2w

174 = L+w = 6+2w+w = 6+3w

3w = 174-6 = 168

w = 56 yds wide

L =6+112 = 118 yds Long