need help solving this

Question

Suppose that the heights of adult women in the United States are normally distributed with a mean of 63.5

inches and a standard deviation of 2.3 inches. Jennifer is taller than 85% of the population of U.S. women. How tall (in inches) is Jennifer? Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.

Answer 1

85% is very close to a z-score of 1. (off by 0.0008)

63.5 + 2.3 = 65.8