A series RL circuit has a total resistance of 2,000 Ω and an inductive reactance of 680 Ω. What phase angle would separate the circuit's current and voltage?

Answer 1

The phase angle can be found as follows. TanΦ= ωL/R where ωL is the inductive reactance and R is the resistance. So tanΦ= 680/2000 = .34 so the phase angle Φ=tan^-1(.34) and Φ= 18.78º.