An experiment has three possible mutually exclusive​ outcomes, A,​ B, or C. If the odds of A occurring are 2 to 6 and the odds of B occurring are 1 to 3​, what are the odds that C​ occurs?

Answer 1

Patrick and Bailee, I agree with everything but the conclusion. Since the probability of getting C is 1/2, then the odds of getting C are 1 to 1, and so are the odds of getting not-C. If the odds of getting C were 1 to 3, the the odds of getting not-C would be 3 to 1.

Answer 2

Prob(A) = 2/8 = 1/4 = 0.25 = 25%

Prob(B) = 1/4 = 0.25%

Prob(C) = 1 - 1/4 - 1/4 = 1/2

Odds of C are 1 to 3