how would you solve this help:( I am so lost here

Question

How would you write this equation also ??? -2/3, -12

Answer 1

(x-[-2/3])(x-[-12])=0

(x+[2/3])(x+12)=0

x²+(2/3)x+12x+(2/3)(12)=0

x²+(12 2/3)x+8=0

x²+(38/3)x+8=0 if you like