
Sanjay S. answered 01/13/15
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Stephanie,
There are 2 ways of solving
A quadratic equation is y = ax^2+bx+c
In this case
y = x^2-2x+1 , so a = 1 and b = -2
Solving for x = -b/2a = -(-2)/(2*1) = 1
or you can solve the equation
x^2 -2x + 1 = 0
x^2 -x -x + 1 = 0
x(x-1) -1(x-1) = 0
(x-1)(x-1) = 0
or x = 1