What is the condition for the equation: ca^2 - (c+1)ab + b^2 to be non-negative? Is this generalizable for anything other than the trivial case of c=1?

Question

When c = 1, the equation reduces to a^2 - 2ab + b^2 which is (a-b)^2 which is non-negative. What happens for other positive values of c (c can never be negative in my equation), assuming a and b are positive quantities?

Answer 1

ca^2-(c+1)ab+b^2

ca^2-abc-ab+b^2

ca is to be +

abc and ab are the same +-.

b is +