Passing through (5,-3) and perpendicular to the line whose equation is x-8y-3=0

Question

The equation of the line in point slope form is

Answer 1

THe given line is:

x - 8y - 3 = 0

adds 8y to both sides:

x - 3 = 8y

divides both sides by 8:

(1/8)(x-3) = y

distributes 1/8

(1/8)x - (3/8) = y

The slope of the given line is 1/8.

The slope of the perpendicular line is -8 and it eats ( 5, -3)

Equation of any line is y = mx + b

b = y - mx

= -3 - (-8)(5)

= -3 - -40

= -3 + 40

= 37

y = (-8)x + 37