Patrick B. answered 07/04/19
Math and computer tutor/teacher
38 choose 6 =
(38*37*36*35*34*33) / (6*5*4*3*2*1) =
38 * 37 * 6 * 35 * 34 * 33 / (5*4*3*2) <---- 6 cancels 36 by factor of 6
38 * 37 * 6 * 7 * 34 * 33 / (4*3*2) <-- 5 cancels 35 by factor of 7
38 * 37 * 6 * 7 * 34 * 11 / (4 * 2) <-- 3 cancels 33 by factor of 11
19 * 37 * 6 * 7 * 34 * 11 / 4 <--- 2 cancels 38
19*37*3 * 7 * 17 * 11 <--- 4 = 2*2 and each two cuts the 6 and 34 in half
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