Need help on this question for math stat.

Question

Listed below are the amounts of mercury ( in parts per million, or ppm) found in tuna sushi sampled at different stores. The sample mean is 1.099 ppm and the sample standard deviation is 0.323 ppm. Use technology to construct a 90% confidence interval estimate of the mean amount of mercury in the population. 0.65 1.08 1.23 0.66 1.29 1.28 1.49

What is the confidence interval estimate of the mean amount of mercury in the population?

_ppm<μ<_ppm

Answer 1

Hi Melissa,

This a very simple questions with STATA. 3 Steps in total,

First, type the 7 numbers by clicking Data Editor and input the numbers. "var1" is automatically given to the series of numbers. Of course you could name it too.

Second, set the confidence interval to 90 percent (the default is 95). *code: "set level 90"

Third, calculate the mean, and it will automatically give you the standard error and the 90% confidence interval. *code: "mean var1"

The answer is 0.8584093 ppm < μ < 1.335876 ppm

Don't know why the screenshots are not allowed to put here. But let me know if you need further illustrations.

Zhao