Patrick B. answered 07/04/19
Math and computer tutor/teacher
The sum of the exterior angles of any regular polygon is always 360
Proof:
The polygon CONTAINS a total of (n-2)*180 degrees.
Each interior angle is (n-2)*180 / n
= (180n - 360) / n
= 180 - 360/n
The supplement is:
180 - (180 - 360/n) = 360/n
The sum of these is n factors of (360/n) , or 360.
end of proof.
Any quadrilateral will suffice.