A parallel-plate capacitor is connected across a potential difference of 40.0 V and stores 360.0 μC of charge. What is the capacitance of the capacitor?

Answer 1

To solve this question, use the equation C=Q/V , where C is capacitance, Q is charge, and V is voltage.

C = 360 microcoulombs/40 volts = 9 microfarads.

The solution is 9 μF, or 9x10^-6 F