
Bob S. answered 06/11/19
Electrical Engineer (PhD), can also help with Physics, Math and Coding
Here's the problem: Prom costs the school $6160. tickets are sold for $40 per single attendee or $70 per couple. if an equal number of singles and couple tickets are sold a minimum of how many people in total must attend the prom to cover its cost.
Let N be the number of single tickets sold at $40. Then N is also the number of couples tickets sold at $70. Therefore we have:
$40 * N + $70 * N = $6160.
Solving for N gives us:
N = $6160 / ($40 + $70) = 6160 / 110 = 56.
So 56 single tickets and 56 couples tickets were sold.
BOb M.
thank you! this helps a lot06/11/19