
Al P. answered 06/10/19
Online Mathematics tutor
What you are describing is the "floor" function:
P = 700 + ⌊(N/50)⌋ * 20
where ⌊x⌋ ≡ floor(x) = { the greatest integer less than or equal to x }
Bethany K.
asked 06/09/19Jasmin gets paid a base salary of $700 a week. She also gets paid an additional $20 for ever 50 items she sells.
I have to write an expression to represent this relationship. I have an equation but I don't know how to make it work for $20 for every 50 items instead of adding a percent of $20 for every item.
P = Pay check N = Number of Items Sold
P = $700 + (N/50) x $20
It works fine if the number of items sold is a multiple of 50 but fails if it any other number
Example:
P = $700 + (50/50) x $20 = $720 It Works!
P = $700 + (82/50) x $20 = $732.8 It fails it should be $720 because she only sold 1 group of 20 items so she should only get an extra $20 not a percent of $20.
How do I fix my equation So it works all the time?
Al P. answered 06/10/19
Online Mathematics tutor
What you are describing is the "floor" function:
P = 700 + ⌊(N/50)⌋ * 20
where ⌊x⌋ ≡ floor(x) = { the greatest integer less than or equal to x }
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Bethany K.
Thank you.06/12/19