Patrick B. answered 06/08/19
Tutor
4.7
(31)
Math and computer tutor/teacher
P = 200*r/ (100*R)^2
= (200*R)/ 10000*R^2
= 1/(50R)
Aisha A.
asked 06/08/19The electric power P dissipated in a resistor of a resistance R equals to 200 times the resistance divided by the square of 100 and the resistance
Patrick B. answered 06/08/19
Math and computer tutor/teacher
P = 200*r/ (100*R)^2
= (200*R)/ 10000*R^2
= 1/(50R)
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.