Preston M. answered 09/20/22
Does math seem like a different language to you?
For the first part, draw out each portion on the graph and you will notice that we are just integrating ƒ(x)=x2 on the interval [0,1]:
∫01x2dx = (x3/3)|01 = 1/3-0/3 = 1/3
Part 2 is analogous. Our bounds are the same but we are integrating ƒ(x)=2x2 now. But notice that we can pull the constant term 2 out of the integral:
2 ∫01x2dx = 2(x3/3)|01 = 2(1/3-0/3) = 2/3