x(x+1)(x+2)

Question

Just tell me the answer

Answer 1

x(x+1)(x+2)

 simply multiply the first bracket with x and then with the total multiply it with the second bracket

x²+x(x+2)

cross multiply:

x³+2x²+x²+2x

x³+3x²+2x

Answer 2

Go for a longer but the simplest method: x(x+1)(x+2)

x(x+1)=(x²+x)

(x²+x)(x+2)=x³+3x²+2x

Answer 3

Not sure if this is a question on finding the roots, if it is:

You look to see what x values can make the whole expression zero. Well all those three quantities (the three sets of parenthesis), are all multiplying together.

x * (x+1) * (x+2). Well the only ways to make something times something equal zero is what... think about that for a second before you read...

 

if one of the something's themselves is zero (8 * 0 = 0 for example). 

With that in mind, what makes the first quantity (x) equal zero? What value makes the second quantity (x+1), equal zero? and the third quantity? Those will be your three options to making the expression as a whole equal zero.

Answer 4

x (x+1) (x+2)=

First distribute the x:

(x²+x) (x+2)= 

Then use the foil method:

(x²*x + x²*2 + x*x + x*2)=

Finally collect the terms and you have:

(x³+3x²+2x)