Just tell me the answer
x(x+1)(x+2)
simply multiply the first bracket with x and then with the total multiply it with the second bracket
x^{2}+x(x+2)
cross multiply:
x^{3}+2x^{2}+x^{2}+2x
x^{3}+3x^{2}+2x
Just tell me the answer
x(x+1)(x+2)
simply multiply the first bracket with x and then with the total multiply it with the second bracket
x^{2}+x(x+2)
cross multiply:
x^{3}+2x^{2}+x^{2}+2x
x^{3}+3x^{2}+2x
Go for a longer but the simplest method: x(x+1)(x+2)
x(x+1)=(x^{2}+x)
(x^{2}+x)(x+2)=x^{3}+3x^{2}+2x
Not sure if this is a question on finding the roots, if it is:
You look to see what x values can make the whole expression zero. Well all those three quantities (the three sets of parenthesis), are all multiplying together.
x * (x+1) * (x+2). Well the only ways to make something times something equal zero is what... think about that for a second before you read...
if one of the something's themselves is zero (8 * 0 = 0 for example).
With that in mind, what makes the first quantity (x) equal zero? What value makes the second quantity (x+1), equal zero? and the third quantity? Those will be your three options to making the expression as a whole equal zero.
x (x+1) (x+2)=
First distribute the x:
(x^{2}+x) (x+2)=
Then use the foil method:
(x^{2}*x + x^{2}*2 + x*x + x*2)=
Finally collect the terms and you have:
(x^{3}+3x^{2}+2x)