Arthur D. answered 12/11/14
Tutor
4.9
(306)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
distance=rate*time
Larry
357=(r)(t+3) and (357)/(t+3)=r
Terrell
216=(r+3)(t)
substitute
216=([357/(t+3)]+3)t
multiply both sides by (t+3)
216(t+3)=(t+3)([357/(t+3)]+3)t
216(t+3)=(357+3(t+3))t
216t+648=357t+3t2+9t
3t2+357t+9t-216t-648=0
3t2+150-648=0
divide by 3
t2+50-216=0
216=2*2*2*3*3*3 and (2*2)(2*3*3*3)=4*54 and 54-4=50
(t+54)(t-4)=0
t-4=0
t=4
357=(r)(4+3)
357=(r)7
r=51 mph for Larry
216=(51+3)4
216=54*4
216=216
r=54 mph for Terrell