find (f*g)(6) f(n)=2n-5 g(n)=n^2-3n

Question

Complicated

Answer 1

f(n) = 2n - 5

g(n) = n² - 3n

 

(f*g)(n) = (2n-5)(n²-3n)

 

     = 2n*n² - 2n*3n - 5*n² + 5*3n

 

     = 2n³ - 11n² + 15n

 

(f*g)(6) = 2*6³ - 11*6² + 15*6

 

Can you finish it from here?