Michelle N. answered • 05/17/19
K-12 Certified Math Tutor /w 10 Years Tutoring Experience
Hi, John!
Let's see what we can do with your equation:
(3+1)^2=(x+1)(x+1) could also be written as
(4)2= (x+1)2. And so, to get rid of the exponent, we'll take a square root of both sides.
4 = ( x + 1). Now we keep in mind that the example said that the inequality will make x a positive number. So
4 = x +1
4 - 1 =x
3 = x
Since 3 is a positive number and all x's need to be positive, we could substitute a ≤ for the = in the first expression to have an x that is always positive.
3 ≤ x
(3+1)^2 ≤ (x+1)(x+1)
Michelle N.
No worries! In that case, the work stays the same, carrying the > down all the way comes up with 3 > x To make x always positive and the equation true, take the answer and add the “x > 0” to the end: 3 > x > 005/17/19
Michelle N.
Please continue to comment if you have any more questions! :)05/17/19
John B.
Thanks! that helped a lot.05/19/19
John B.
Silly me, I meant the equation to be (3+1)^2 > (x+1)(x+1) not (3+1)^2 = (x+1)(x+1). Plus I can’t put equal or less than sign for some reason05/17/19