day 0: 40
day 1: 40r
day 2: 40r^2
day 3: 40r^3
...
day 16: 40r^16 =10 Solve for r
...
day 20: 40r^20 -...
Kelly H.
asked 04/15/19The mass of an isotope decreases at a rate that is proportional to the mass at that time. The mass of the isotope was 40 grams initially and it was 10 grams after 16 days.
day 0: 40
day 1: 40r
day 2: 40r^2
day 3: 40r^3
...
day 16: 40r^16 =10 Solve for r
...
day 20: 40r^20 -...
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