One positive number is 4 more than another. The sum of their squares is 40. Find the numbers

Answer 1

x^2 + (x+4)^2 = 2x^2 + 8x +16 = 40

x^2 +4x +8 = 20

x^2 +4x - 12 =0

(x+6)(x-2) = 0

x = -6 or 2

y = -2 or 6

two solutions (x,y) = (2,6) or (-6,-2)