How do you write an equation in standard form if the line passes through (7,-3) and (4,1)

Answer 1

(7,-3), (4,1) have a line through them with slope = "rise over run" = (1+3)/(4-7) = -4/3

line's equation is y+3 = (-4/3)(x-7) in point slope form

or y = -4x/3 +28/3 -3

y = (-4/3)x +19/3 in slope intercept form

or

3y = -4x +19

4x +3y = 19 in standard form