How many different codes an a combination have if there are 3 numbers on the lock and each number can be from 0-9?

Answer 1

So for the first digit, we have 10 possible choices of number to choose from (0-9)

For the second digit, we again have 10 possible choices.

And for the third digit, we have 10 possible choices again.

Thus, the total number of choices we have is: 10 x 10 x 10 = 1000