
William M. answered 03/28/19
William M. - Effective Tutor focusing on English, Writing and Math
Break down the 1296 into smaller SQRT's.
The SQRT 1296 = (SQRT 4) (SQRT 324) = (SQRT 4)(SQRT 4)(SQRT 81) = (2)(2)(9) =36
Jolene B.
asked 03/28/19other than trial and error - how do you solve for l from that point?
William M. answered 03/28/19
William M. - Effective Tutor focusing on English, Writing and Math
Break down the 1296 into smaller SQRT's.
The SQRT 1296 = (SQRT 4) (SQRT 324) = (SQRT 4)(SQRT 4)(SQRT 81) = (2)(2)(9) =36
Taking the square root isn't a simple operation like taking the square is. So we can't just so this directly. We have to get some clues and go from there.
So, we need a number that, when it gets multiplied by itself, gives me a number that ends in 6. What could the two numbers be?
1*1 = 1.
2*2 = 4
3*3 = 9
4*4 = 16 (this one ends in a 6)
5*5 = 25
6*6 = 36 (this one also ends in a 6)
7*7 = 49
8*8 = 64
9*9 = 81.
So we know that our number has to end in a 4 or a 6. So, 4, 6, 14, 16, 24, 26, etc. are numbers that might work. Let's look at squares of the multiples of 10 now.
10*10 = 100 (smaller than 1296)
20*20 = 400 (smaller than 1296)
30*30 = 900 (smaller than 1296)
40*40 = 1600 (bigger than 1296)
So we know our number has to be between 30 and 40.
Also 1296 is divisible by 3 (because 1+2+9+6 = 18, which is divisible by 3, and that's the divisibility rule for 3)
So we need a number between 30 and 40 that ends in 4 or 6 AND is a multiple of 3.
36 is our only choice. We then verify: 36*36 = 1296.
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