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Question

boxes A & B contained 112 pencils. when 1/5 of the pencils in box A were transferred to box B both boxes contained the same number of pencils. how many more pencils were there in box A than in box B at first

Answer 1

You would first need to find the number of pencils that equals a fifth of box A by dividing 112 by 5. Then that number represents the amount that box B was missing. Then you take the number of pencils in the boxes when they are equal and subtract the fifth you found to get how many were in box B originally.